std::remove_copy, std::remove_copy_if

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Defined in header <algorithm>

template< class InputIterator, class OutputIterator, class T >

OutputIterator remove_copy( InputIterator first,
                            InputIterator last,
                            OutputIterator d_first,

                            const T& value );
(1)
template< class InputIterator, class OutputIterator, class UnaryPredicate >

OutputIterator remove_copy_if( InputIterator first,
                               InputIterator last,
                               OutputIterator d_first,

                               UnaryPredicate p );
(2)

Copies elements from the range [first, last), to another range beginning at d_first, omitting the elements which satisfy specific criteria. The first version ignores the elements that are equal to value, the second version ignores the elements for which predicate p returns true. Source and destination ranges cannot overlap.

Contents

[edit] Parameters

first, last - the range of elements to copy
d_first - the beginning of the destination range.
value - the value of the elements not to copy

[edit] Return value

iterator to the element past the last element copied.

[edit] Complexity

Exactly last - first applications of the predicate.

[edit] Equivalent function

[edit] Example

The following code outputs a string while erasing the spaces on the fly.

#include <algorithm>
#include <iterator>
#include <string>
#include <iostream>
int main()
{
    std::string str = "Text with some   spaces";
    std::cout << "before: " << str << "\n";
 
    std::cout << "after:  ";
    std::remove_copy(str.begin(), str.end(),
                     std::ostream_iterator<char>(std::cout), ' ');
    std::cout << '\n';
}

Output:

before: Text with some   spaces
after:  Textwithsomespaces

[edit] See also

remove
remove_if
removes elements satisfying specific criteria
(function template)